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已知函数Fx=2Cosxsin(x加三分之派)%根号三sin平...

f(x) = sin(π/2-x)sinx - √3cos²x = cosxsinx - √3cos²x = 1/2sin2x - √3/2cos2x - √3/2 = sin2xcosπ/3-cos2xsinπ/3 - √3/2 = sin(2x-π/3) - √3/2 最小正周期:2π/2 = π 最大值:1 - √3/2 = (2-√3)/2

fx=2cosxsin(x+π/3)-√3sin^2x+sinxcosx+1 =2cosx(√3/2cosx+1/2sinx)-√3sin^2x+sinxcosx+1 =√3cos^2x-√3sin^2x+2sinxcosx+1 =√3cos2x+sin2x+1 =2(√3/2cos2x+1/2sin2x)+1 =2sin(2x+π/3)+1 T=2π/2=π

1.F{x}=2sin{2x+∏/3} 当函数f(x)的单调递减区间时∏/2 + +2k∏《2x++∏/3《3∏/2 +2k∏〈k取任意整数〉,解的∏/12 + k∏〈x〈7∏/12 +k∏ 2。将函数f(x)的图象按向量a=(m,0) 平移 可设 平移后 函数中的x为x” Y为y” x”=x+m Y”=y 所以 平移后的 函数...

f(x)=4cosxsinx-4sin(x +派/3)cosx +根号3 =2sin2x-4(1/2*sinx+根号3/2*cosx)cosx+根号3 =2sin2x-(2sin2x+2根号3cos平方x)+根号3 =根号3-2根号3cos平方x

f(x)=√3/2sin2x-(cosx)²-½ =√3/2sin2x-1/2cos2x-1 =sin(2x-π/6)-1 T=2π/2=π 2x-π/6在[2kπ+π/2,2kπ+3π/2]是调递减 x在[kπ+π/3,kπ+5π/6]是调递减

f(x)=[2sin(x+π/3)+sinx]cosx-根号3sin^2x和差角公式展开f(x)=(sinx+根号3cosx+sinx)cosx-根号3sin2x=2sinx*cosx+根号3cosx*cosx-根号3sin2x降幂公式f(x)=sin2x+根号3*(1+cos2x)/2-根号3sin2x=(1-根号3)sin2x+根号3/2cos2x+根号3/2 辅助角公...

已知函数f(x)=2sin²x+2根号3sinxcosx+1,求函数的单调递增区间 函数在区间【0,п/2】上的最值 解析:∵函数f(x)=2sin²x+2√3sinxcosx+1=-cos2x+√3sin2x+2 =2sin(2x-π/6)+2 其单调增区间为: 2kπ-π/2

解: 已知△ABC中,AB=AC,BD⊥AC,且BD=1/2AB 求∠BAC的度数 解:作BD⊥AC,交直线AC于点D (1)当点D在AC上时 ∵BD=1/2AB ∴∠BAC=30° (2)当点D在CA的延长线上时, ∵BD=1/2AB ∴∠BAD=30° ∴∠BAC=150° f'(x)=2x-m/x, h'(x)=2x-1, 取f'(x)=0,得m=2x^2;x=√m/2,...

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